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A coffee shop owner tracks daily earnings:
[100, -50, 200, -30, 150, -20, 300]
Some days are great, some are bad.
But the owner isn’t interested in just one day.
He wants to know:
“Which continuous stretch of days gave me the highest profit?”
Not random days.
Not scattered choices.
Only continuous days.
That’s exactly what a subarray is.

A subarray is a continuous part of an array.
| Array: [1, 2, 3, 4] Subarrays: [1], [2], [3], [4] [1,2], [2,3], [3,4] [1,2,3], [2,3,4] [1,2,3,4] |
Important:
You try every possible subarray and calculate the sum.
| def max_subarray_brute(arr): max_sum = float('-inf') for i in range(len(arr)): for j in range(i, len(arr)): current_sum = sum(arr[i:j+1]) max_sum = max(max_sum, current_sum) return max_sum |
Problem:
Kadane’s Algorithm (The Smart Insight)
Instead of checking everything, we think smart:
“If the current sum becomes negative, drop it!”
Because a negative sum will only reduce future profit.
Concept - Maximum Subarray Sum
| def kadane(arr): current_sum = arr[0] max_sum = arr[0] for num in arr[1:]: current_sum = max(num, current_sum + num) max_sum = max(max_sum, current_sum) return max_sum |
Technical Example:
Input:
[-2, 1, -3, 4, -1, 2, 1, -5, 4]
Output:
6 → subarray [4, -1, 2, 1]
Real-Life Insight:
This is optimization thinking
Sliding Window (Fixed Size Subarrays)
Sometimes interviewer asks:
“Find maximum sum of subarray of size k”
Example:
| [2, 1, 5, 1, 3, 2], k = 3 |
Concept - Window Moves Forward
| def max_sum_k(arr, k): window_sum = sum(arr[:k]) max_sum = window_sum for i in range(k, len(arr)): window_sum += arr[i] - arr[i-k] max_sum = max(max_sum, window_sum) return max_sum |
Time Complexity = O(n)
Real-Life Example:
Finding the best 3-day sales period without recalculating everything.
Interviewers don’t say “subarray problem”.
They say things like:
All are hints toward subarray techniques

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